Re: [PATCH] btrfs: Simplify len alignment calculation

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On 3.12.19 г. 9:52 ч., Omar Sandoval wrote:
> On Fri, Nov 29, 2019 at 11:38:07AM +0200, Nikolay Borisov wrote:
>> Use ALIGN() directly rather than achieving the same thing in a roundabout way.
>> No semantic changes.
>>
>> Signed-off-by: Nikolay Borisov <nborisov@xxxxxxxx>
>> ---
>>  fs/btrfs/delalloc-space.c | 3 +--
>>  1 file changed, 1 insertion(+), 2 deletions(-)
>>
>> diff --git a/fs/btrfs/delalloc-space.c b/fs/btrfs/delalloc-space.c
>> index 4cdac4d834f5..c08e905b0424 100644
>> --- a/fs/btrfs/delalloc-space.c
>> +++ b/fs/btrfs/delalloc-space.c
>> @@ -142,8 +142,7 @@ int btrfs_check_data_free_space(struct inode *inode,
>>  	int ret;
>>
>>  	/* align the range */
>> -	len = round_up(start + len, fs_info->sectorsize) -
>> -	      round_down(start, fs_info->sectorsize);
>> +	len = ALIGN(len, fs_info->sectorsize);
> 
> Consider sectorsize = 4096, start = 4095, len = 2. This range spans two
> blocks, which is what the original compuation gives. Yours returns one
> block instead.
> 

Doh, you are right. I copied this approach from your [RFC PATCH v3
09/12] btrfs: support different disk extent size for delalloc patch.
Doesn't it suffer from the same bug?



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