On 31.01.2018 11:28, Anand Jain wrote:
>
>
> On 01/31/2018 04:38 PM, Nikolay Borisov wrote:
>>
>>
>> On 30.01.2018 08:30, Anand Jain wrote:
>>> Adds the mount option:
>>> mount -o read_mirror_policy=<devid>
>>>
>>> To set the devid of the device which should be used for read. That
>>> means all the normal reads will go to that particular device only.
>>>
>>> This also helps testing and gives a better control for the test
>>> scripts including mount context reads.
>>
>> Some code comments below. OTOH, does such policy really make sense, what
>> happens if the selected device fails, will the other mirror be retried?
>
> Everything as usual, read_mirror_policy=devid just lets the user to
> specify his read optimized disk, so that we don't depend on the pid
> to pick a stripe mirrored disk, and instead we would pick as suggested
> by the user, and if that disk fails then we go back to the other mirror
> which may not be the read optimized disk as we have no other choice.
>
>> If the answer to the previous question is positive then why do we really
>> care which device is going to be tried first?
>
> It matters.
> - If you are reading from both disks alternatively, then it
> duplicates the LUN cache on the storage.
> - Some disks are read-optimized and using that for reading and going
> back to the other disk only when this disk fails provides a better
> overall read performance.
So usually this should be functionality handled by the raid/san
controller I guess, but given that btrfs is playing the role of a
controller here at what point are we drawing the line of not
implementing block-level functionality into the filesystem ?
>
> ::
>>> diff --git a/fs/btrfs/volumes.c b/fs/btrfs/volumes.c
>>> index 39ba59832f38..478623e6e074 100644
>>> --- a/fs/btrfs/volumes.c
>>> +++ b/fs/btrfs/volumes.c
>>> @@ -5270,6 +5270,16 @@ static int find_live_mirror(struct
>>> btrfs_fs_info *fs_info,
>>> num = map->num_stripes;
>>> switch(fs_info->read_mirror_policy) {
>>> + case BTRFS_READ_MIRROR_BY_DEV:
>>> + optimal = first;
>>> + if (test_bit(BTRFS_DEV_STATE_READ_MIRROR,
>>> + &map->stripes[optimal].dev->dev_state))
>>> + break;
>>> + if (test_bit(BTRFS_DEV_STATE_READ_MIRROR,
>>> + &map->stripes[++optimal].dev->dev_state))
>>> + break;
>>> + optimal = first;
>>
>> you set optimal 2 times, the second one seems redundant.
>
> No actually. When both the disks containing the stripe does not
> have the BTRFS_DEV_STATE_READ_MIRROR, then I would just want to
> use first found stripe.
Yes, and the fact that you've already set optimal = first right after
BTRFS_READ_MIRROR_BY_DEV ensures that, no ? Why do you need to again set
optimal right before the final break? What am I missing here?
>
>> Alongside this
>> patch it makes sense to also send a patch to btrfs(5) man page
>> describing the mount option + description of each implemented allocation
>> policy.
>
> Yep. Will do.
>
>> Another thing which I don't see here is how you are handling the case
>> when you have more than 2 devices in the RAID1 case. As it stands
>> currently you assume there are two devices and first test device 0 and
>> then device 1 and completely ignore any other devices.
>
> Not really. That part is already handled by the extent mapping.
> As the number of stripe for raid1 is two, the extent mapping will
> manage put related two devices of this stripe.
>
> Thanks, Anand
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