Hello,
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I apologize beforehand if I'm asking a too basic question for the
mailing list, or if it has been already answered at nauseam.
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I have two hdd (Western Digital 750 GB approx. 700 GiB each), and I
planning to set up a RAID 0 through btrfs. UEFI firmware/boot, no dual
boot, only linux.
My question is, given the UEFI partition plus linux swap partition, I
won't have two equal sized partitions for setting up the RAID 0 array.
So, I'm not quite sure how to do it. I'll have:
/dev/sda:
16 KiB (GPT partition table)
sda1: 512 MiB (EFI, fat32)
sda2: 16 GiB (linux-swap)
sda3: rest of the disk / (btrfs)
/dev/sdb:
sdb1: (btrfs)
The btrfs partitions on each hdd are not of the same size (admittedly by
an small difference, but still). Even if a backup copy of the EFI
partition is created in the second hdd (i.e. sdb) which it may be, not
sure, because the linux-swap partion is still left out.
Should I stripe both btrfs partitions together no matter the size?
mkfs.btrfs -m raid0 -d raid0 /dev/sda3 /dev/sdb1
How will btrfs manage the difference in size?
Or should I partition out the extra size of /dev/sdb for trying to match
equally sized partions? in other words:
/dev/sdb:
sdb1: 17 GiB approx. free or for whatever I want.
sdb2: (btrfs)
and then:
mkfs.btrfs -m raid0 -d raid0 /dev/sda3 /dev/sdb2
Again, I'm sorry if it's an idiotic question, but I don't have it quite
clear and I would like to do it properly. So, any hint from more
knowable users would be MUCH appreciate it.
Thanks in advance.
JM.
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