Re: [PATCH 4/4] Default to acting like fsck.

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On 21 September 2014 13:59, Tobias Geerinckx-Rice
<tobias.geerinckx.rice@xxxxxxxxx> wrote:
> On 21 September 2014 03:01, Dimitri John Ledkov <xnox@xxxxxxxxxx> wrote:
>>
>> Inspect arguments, if we are not called as btrfs, then assume we are
>> called to act like fsck.
> [...]
>> -       if (!strcmp(bname, "btrfsck")) {
>> +       if (strcmp(bname, "btrfs") != 0) {
>
> That's assuming a lot.
>
> Silently (!) breaking people's btrfs-3.15_patched-DontRandomlyPanicV2
> is a recipe for needless hair-pulling. Is there a reason for not using
> something less like strstr(bname, "fsck") that I am missing?
>

Quite. This is verbatim patch as I have currently applied in Debian
packaging, and it was a fast fix to prevent breakage we had at one
point.

Indeed using "strstr(bname, "fsck")" would be better and sufficient to
resolve the problem we encountered (specifically fsck.btrfs -> btrfs
not acting like btrfs). Also using strstr, would fix btrfsck.my-build
to act like fsck tool.

I'll update this one patch.

-- 
Regards,

Dimitri.
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