Re: [PATCH V2 2/4] Btrfs: don't get the lock when adding a csum into a ordered extent

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On 01/14/2014 07:31 AM, Miao Xie wrote:
We are sure that:
- one ordered extent just has one csum calculation worker, and no one
   access the csum list during the csum calculation except the worker.
- we don't change the list and free the csum until no one reference
   to the ordered extent
So it is safe to add csum without the lock.

Signed-off-by: Miao Xie <miaox@xxxxxxxxxxxxxx>
---
  fs/btrfs/ordered-data.c |    5 -----
  1 files changed, 0 insertions(+), 5 deletions(-)

diff --git a/fs/btrfs/ordered-data.c b/fs/btrfs/ordered-data.c
index e4c3d56..396c6d1 100644
--- a/fs/btrfs/ordered-data.c
+++ b/fs/btrfs/ordered-data.c
@@ -280,16 +280,11 @@ void btrfs_add_ordered_sum(struct inode *inode,
  			   struct btrfs_ordered_extent *entry,
  			   struct btrfs_ordered_sum *sum)
  {
-	struct btrfs_ordered_inode_tree *tree;
-
-	tree = &BTRFS_I(inode)->ordered_tree;
-	spin_lock_irq(&tree->lock);
  	list_add_tail(&sum->list, &entry->list);
  	WARN_ON(entry->csum_bytes_left < sum->len);
  	entry->csum_bytes_left -= sum->len;
  	if (entry->csum_bytes_left == 0)
  		wake_up(&entry->wait);
-	spin_unlock_irq(&tree->lock);
  }
/*
This blew up in xfstests so one of your assumptions is incorrect. Thanks,

Josef
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