On 22.04.20 13:06, Hugo Mills wrote:
"It is possible with all of the descriptions below, to construct a RAID-1
array from two or more devices, and have those devices live on the same
physical drive. This configuration does not offer any form of redundancy for
your data."
There's a difference between "device" and "disk" here. If you make
two partitions on one device, and that device fails, then there's no
(disk) redundancy.
If you make two partitions on one disk and one partition on another
disk, and use all three partitions (block devices) to make a RAID-1,
then you're still going to lose the filesystem if the disk with two
partitions on it fails.
OK, this makes sense to me and cleared things up.
I still do not get the clue why it is explicitly mentioned in the wiki
that there will be no redundany for the data if one uses just one disk
in case of a disk failure. This is pretty obvious instead.
Thanks,
Steffi
