From: Subramaniam Appadodharana <c.a.subramaniam@xxxxxxxxx>
To: Tao Jiang <jiangtao.jit@xxxxxxxxx>
Cc: Graeme Russ <graeme.russ@xxxxxxxxx>; Bernd Petrovitsch
<bernd@xxxxxxxxxxxxxxxxxxx>; Peter Senna Tschudin <peter.senna@xxxxxxxxx>; kernelnewbies@xxxxxxxxxxxxxxxxx
Sent: Monday, February 20, 2012 8:53:10 AM
Subject: Re: How to figure out the byteorder only with one byte number?
On Mon, Feb 20, 2012 at 5:25 AM, Tao Jiang <jiangtao.jit@xxxxxxxxx
> Thank you all.
> Take a byte number 0b00000001 for example
> ^ ^
> high bit low
> I used to think in a LE machine it will be stored as 0b10000000 low bit first
> ^ ^
> low bit high bit
> and in a BE machine will be 0b00000001 high bit first
> ^ ^
> high bit low bit
> not only the byteorder is different, but inside a byte is also different.
> But actually they are the same, right?
yes they are same. In fact it is termed as 'byte' order not
order. Hope this helps.
> Thank you.
> 2012/2/20 Graeme Russ <graeme.russ@xxxxxxxxx
>> On 02/20/2012 01:24 AM, Bernd Petrovitsch wrote:
>>> On Sun, 2012-02-19 at 20:08 +0800, Tao Jiang wrote:
>>>> Is there some difference of the storge between BE and LE machine inside a byte?
>>> No. At least TTBOMK there exists no such hardware.
>> Using SHL/SHR would tell you - SHL normally results in a multiply by 2, SHR
>> a divide by 2. If the byte was little endian, the results would be visa-versa
>> But I agree, I doubt there is any such hardware
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