Question on flow of control at the time of interrupt.

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Subject: Question on flow of control at the time of interrupt.
From: "sahlot arvind" <asahlot@xxxxxxxxx>
Date: Fri, 25 Apr 2008 14:31:20 +0530

Guys,

I am trying to understand the flow of control when an interrupt comes.

I am reading linux-2.6.24 src code and looking at arch/arm/kernel/entry-armv.S.

At the bottom of this file I see the vector table as below -

__vectors_start:
    swi SYS_ERROR0
    b   vector_und + stubs_offset
    ldr pc, .LCvswi + stubs_offset
    b   vector_pabt + stubs_offset
    b   vector_dabt + stubs_offset
    b   vector_addrexcptn + stubs_offset
    b   vector_irq + stubs_offset
    b   vector_fiq + stubs_offset

.globl __vectors_end

Here is not 'stubs_offset' a constant? and after seeing an IRQ where are we branching by doing ' b vector_irq + stubs_offset' and what is the flow of control???

Thanks in advance.

- A Sahlot
--
http://linuxexplained.blogspot.com

Follow-Ups:
- Re: Question on flow of control at the time of interrupt.
  - From: Russell King - ARM Linux
- Re: Question on flow of control at the time of interrupt.
  - From: eric miao

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