- Subject: Basic dummy iptables SNAT multiple IPs algorithm question
- From: Mihai Tanasescu <mihai@xxxxxxxx>
- Date: Fri, 10 Feb 2012 15:46:58 +0100
- User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv:8.0) Gecko/20111105 Thunderbird/8.0
Hi guys,
I've been using iptables and some of the modules it comes with for a
while now but only recently as I stumbled into a big NAT444 setup, did I
reach the point at which I'd like to find an answer to a theoretical
question.
I wanted to ask:
If I have a rule that says:
iptables -t nat -A POSTROUTING -o eth0 -s 192.168.0.0/16 -j SNAT --to
20.20.20.1-20.20.20.22.254
Then how are the IPs from the private pool distributed to the ones from
the public pool in the two following cases:
- with persistent
- with random
Is it a simple mathematical thing like:
if private pool has X IPs ( 65536 in this case) and public Pool (Y) has
let's say 766 IPs in theory => X / Y = aprox 85 private IPs per public
IP and then:
- 192.168.0.0-84 => 20.20.20.1
- 192.168.0.85-169 => 20.20.20.2
and so on ?
or does this depend on the number of IPs which are online and the
algorithm is a bit more complex ?
Also, what happens in case random is being used to the same algorithm ?
Hope I'm not troubling you too much with theory related questions.
Thanks,
Mihai
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