Re: Query: Declaring arrays as extern

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Hi Viresh,

I think this is what's happening in your case.

Imagine array address is 0x1000 and the contents stored are 1,2,3,4...10.
So when you access  it as a pointer int *array,address of array will
get 0x1000 and array variable will have the
value 1.So when you print it the value will be 1 and when you
dereference it,it will try to fetch from 0x1.

On Thu, Dec 22, 2011 at 3:04 AM, viresh kumar <viresh.linux@xxxxxxxxx> wrote:
> On Thu, Dec 22, 2011 at 2:34 PM, viresh kumar <viresh.linux@xxxxxxxxx> wrote:
>> Hi,
>>
>> I can observing an behavior which i am not able to explain.
>
>   I am
>
> sorry. :)
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Subin Gangadharan

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