Re: getting at raw command line

[Lukas <blurrpp@xxxxxxxxx>]

of course in last line of "code" ;) should be %ebx=42

regards
Lukas

--- Lukas <blurrpp@xxxxxxxxx> wrote:

> As i said, when you start program 'p whatever ' %esp
> points place on stack where number of parameters was
> put ex. 
> $p 1 2 3 -> movl (%esp),%ecx => %ecx=3 )
> 
> next (%esp+4) adress of program name ex. 
> 
> $/home/usr/bin/p 1 2 3 -> (%esp+4) adres of string
> "/home/usr/bin/p"
> 
> (%esp+8)(+16 if you have 64-bit arch) adress of text
> string of first parameter, so if you write
> 
> $ p * -> movl (%esp+8),%ecx / movq (%rsp+16),%rcx
>         movl (%ecx),%ebx / movq (%rcx),%rbx
>        %ecx=42 ( '*' )
> so now you can do with it whatever you want ( write
> using SYS_WRITE, printf etc )
> Lukas
> 
> 
> --- Jack Andrews <effbiae@xxxxxxxxx> wrote:
> 
> > the shell changes arguments like * to a number of
> > arguments.  is there
> > a way to get the *?  that is, if my program is p,
> i
> > want this
> > behaviour:
> > 
> >  $ ls
> >  file.1 file.2
> >  $ ls *
> >  file.1 file.2
> >  $ p file.1
> >  file.1
> >  $ p *
> >  *
> > 
> > i don't want
> > 
> >  $ p *
> >  file.1 file.2
> > -
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> 
> 
> 
>        
>
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