Re: error: unable to find numeric literal operator ‘operator"" f’

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On 13 February 2014 03:23, Florian Weimer wrote:
>
> I think the ""f operator has not been implemented in C++1y mode, either
> because it's not actually part of the standard or no one has found the time
> to implement it yet.

f is not a user-defined literal operator, it's a core language feature
present in C and C++, but not valid on integer-literals such as 42.




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