Re: GCC's -ffast-math behavior

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于 2012/2/9 17:21, Andrew Haley 写道:
On 02/09/2012 08:33 AM, xunxun wrote:
         When using -ffast-math, gcc don't generate the math function
symbol: U _exp
No, it doesn't.  Instead gcc uses the F2XM1 instruction.  Why would
you want to call a library when gcc has an instruction to do the
job?

Andrew.


Because other math lib works faster than gcc itself (even with fastmath), and I want to use fastmath to make other caculation faster, too.

--
Best Regards,
xunxun



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