Dear friends This is my simple dialplan [demopjsip] exten => _X.,1,Dial(PJSIP/${EXTEN}@10.10.10.2) exten => _X.,n,Hangup() I need to dial out via an IP address, not using an endpoint, as shown above. It fails with Executing [19544447408@demopjsip:3] Dial("PJSIP/federico-00000002", "PJSIP/195XXX7408@10.10.10.2") in new stack [Jun 26 00:39:00] ERROR[10136]: chan_pjsip.c:1722 request: Unable to create PJSIP channel - endpoint '10.10.10.2' was not found [Jun 26 00:39:00] WARNING[10167][C-00000002]: app_dial.c:2421 dial_exec_full: Unable to create channel of type 'PJSIP' (cause 3 - No route to destination) I remember that this Dial format was possible with regular SIP. The IP address is routable, so there is no specific network issue. In my pjsip.coonf I defined a default outbound endpoint [global] default_outbound_endpoint=default_outbound_endpoint In that default endpoint defined, I did not add any IP address, because I want to keep it generic and dial any IP address with the same settings, Is this possible? -- _____________________________________________________________________ -- Bandwidth and Colocation Provided by http://www.api-digital.com -- New to Asterisk? Join us for a live introductory webinar every Thurs: http://www.asterisk.org/hello asterisk-users mailing list To UNSUBSCRIBE or update options visit: http://lists.digium.com/mailman/listinfo/asterisk-users