About memory mapping

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Hi,

In my ARM Board,  when I input  "cat /proc/self/maps"
I get following messages:

00008000-000d3000 r-xp 00000000 b3:02 23508      /bin/busybox
000db000-000dc000 rwxp 000cb000 b3:02 23508      /bin/busybox
000dc000-000ff000 rwxp 00000000 00:00 0          [heap]
40000000-4001e000 r-xp 00000000 b3:02 7836       /lib/ld-2.10.1.so
4001e000-40020000 rwxp 00000000 00:00 0
40025000-40026000 r-xp 0001d000 b3:02 7836       /lib/ld-2.10.1.so
40026000-40027000 rwxp 0001e000 b3:02 7836       /lib/ld-2.10.1.so
40027000-400c0000 r-xp 00000000 b3:02 7850       /lib/libm-2.10.1.so
400c0000-400c7000 ---p 00099000 b3:02 7850       /lib/libm-2.10.1.so
400c7000-400c8000 r-xp 00098000 b3:02 7850       /lib/libm-2.10.1.so
400c8000-400c9000 rwxp 00099000 b3:02 7850       /lib/libm-2.10.1.so
400c9000-40204000 r-xp 00000000 b3:02 7835       /lib/libc-2.10.1.so
40204000-4020b000 ---p 0013b000 b3:02 7835       /lib/libc-2.10.1.so
4020b000-4020d000 r-xp 0013a000 b3:02 7835       /lib/libc-2.10.1.so
4020d000-4020e000 rwxp 0013c000 b3:02 7835       /lib/libc-2.10.1.so
4020e000-40211000 rwxp 00000000 00:00 0
bedc7000-beddc000 rw-p 00000000 00:00 0          [stack]


What is this anonymous mapping(4020e000-40211000 rwxp 00000000 00:00 0)?

Thanks.

Mingli

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