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About memory mapping | |
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Hi, In my ARM Board, when I input "cat /proc/self/maps" I get following messages: 00008000-000d3000 r-xp 00000000 b3:02 23508 /bin/busybox 000db000-000dc000 rwxp 000cb000 b3:02 23508 /bin/busybox 000dc000-000ff000 rwxp 00000000 00:00 0 [heap] 40000000-4001e000 r-xp 00000000 b3:02 7836 /lib/ld-2.10.1.so 4001e000-40020000 rwxp 00000000 00:00 0 40025000-40026000 r-xp 0001d000 b3:02 7836 /lib/ld-2.10.1.so 40026000-40027000 rwxp 0001e000 b3:02 7836 /lib/ld-2.10.1.so 40027000-400c0000 r-xp 00000000 b3:02 7850 /lib/libm-2.10.1.so 400c0000-400c7000 ---p 00099000 b3:02 7850 /lib/libm-2.10.1.so 400c7000-400c8000 r-xp 00098000 b3:02 7850 /lib/libm-2.10.1.so 400c8000-400c9000 rwxp 00099000 b3:02 7850 /lib/libm-2.10.1.so 400c9000-40204000 r-xp 00000000 b3:02 7835 /lib/libc-2.10.1.so 40204000-4020b000 ---p 0013b000 b3:02 7835 /lib/libc-2.10.1.so 4020b000-4020d000 r-xp 0013a000 b3:02 7835 /lib/libc-2.10.1.so 4020d000-4020e000 rwxp 0013c000 b3:02 7835 /lib/libc-2.10.1.so 4020e000-40211000 rwxp 00000000 00:00 0 bedc7000-beddc000 rw-p 00000000 00:00 0 [stack] What is this anonymous mapping(4020e000-40211000 rwxp 00000000 00:00 0)? Thanks. Mingli 使用Messenger保护盾V2,支持多账号登录! 现在就下载! |
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